|
 |
 |
|
|
Fig. 199 - Horse barn with |
|
open Queenpost truss roof |
|
|
|
(scale visualization model) |
|
click image to enlarge |
|
|
. |
|
The
sloped plane of the roof must also be stabilized with some sort of bracing
to keep the |
|
trusses
from tipping over (braces are indicated by blue pinges). |
|
 |
 |
◄
Fig. 200 - Bracing roof |
|
trusses to keep them |
|
from tipping over |
|
(static demonstration model) |
|
|
|
|
Combining all of these planes together gives an |
 |
|
idealized model of a completely stabilized |
|
house framework complete with bracing. |
|
|
|
Fig. 201 - Stable skeletal framework of a house ► |
|
(static demonstration model) |
|
|
|
|
Lattice action |
|
. |
|
Thus far
our stability analysis of a home's framework has treated the structure as
though it |
|
was
comprised of discrete triangulated planes in order to simplify the
stability analysis. |
|
This
approach is similar to treating polyhedra as though they are assemblies of
discrete |
|
planar
faces, which of course they are. However, we can also do a stability
analysis of the |
|
entire
three-dimensional structure by using another equation Euler devised for
polyhedra: |
|
. |
|
M = 3 ( J ) - 6 where M = members |
|
J = joints |
|
. |
|
Lets
apply it to the house framework you just studied. For example, the
stabilized cube has |
|
a total
of 18 members (12 edges plus 6 diagonal braces) and 8 joints.
Substituting these |
|
values
into Euler's equation gives 18 = 3 ( 8 ) - 6, confirming that it is
stable. |
|
 |
 |
 |
|
a) stabilized cube |
b) stabilized roof |
c) stabilized house |
|
18 = 3 ( 8 ) - 6 |
12 = 3 ( 6 ) - 6 |
24 = 3 ( 10 ) - 6 |
|
stable |
stable |
stable |
|
click image to enlarge |
|
Fig. 202 - Analyzing the stability of
idealized lattice frameworks with M = 3 ( J ) - 6 |
|
|
. |
|
Back
to Knowhere |
|
 |
Page 119
- Building stability - Lattice action |
 |
|