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Truncating
the Platonic solids to create the Archimedean solids |
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Symmetrically truncating the vertices of the regular Platonic solids creates most |
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of the
semi-regular Archimedean solids. This permits the symmetry of the latter to |
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be associated
with the former in a straightforward manner. For example the cube |
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and octahedron
can be progressively truncated to yield the cuboctahedron. The |
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Fig. 13a |
Fig. 13b |
Fig. 13c |
Fig. 13d |
Fig. 13e |
Truncated
cube |
Truncated |
Cuboctahedron |
Truncated |
Octahedron |
in a cube |
cube |
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octahedron |
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Required
parts |
8
large triangles |
8
triangles |
48 triangles |
8 triangles |
6
large squares |
6 squares |
6 squares |
12 pinges |
24
rectangles |
24 pinges |
84
pinges |
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24
right triangles (48 for 13a) |
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96
pinges (120 for 13a) |
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Fig. 13 -
Truncating the cube and octahedron to make the cuboctahedron |
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truncated cube
and the truncated octahedron are generated in the process. Since |
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each vertex of
the polyhedra are symmetrically sliced off the resulting polyhedra |
retain the same
symmetry elements as the original. |
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Exercise: Truncating the vertices
of which polyhedron produces the triangle |
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faces of the cuboctahedron? Which
one produces the square's? Why? |
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Page 11
Geometry rules! - Symmetry association by truncation |